i got 89 percentile in jee mains paper 2,what will be the rank?
New: Direct link to apply for JEE Main 2025 registration for session 1
Also Check: Crack JEE Main 2025 - Join Our Free Crash Course Now!
JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQs | Video Lectures
JEE Main 2025: Preparation Guide | High Scoring Topics | Study Plan 100 Days
.
Use this formula to predict the rank:
.
Rank Formula = (100 - your total score) X 145386 /100.
Your rank 15992 by using above formula.
Your rank may differ from the official cutoff and results which were released on the month of April by national testing agency NTA officially.
.
You have to wait for the official results.
if you want to compare with previous years cutoff of b.arch .you can go through the below link:
.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
.
If you have any questions further let me know.
.
Thank you!!!
.
Hey.
You can use the formula given below to calculate JEE B.Arch Rank from your percentile-
(100- your total percentile score) * 1,45,386/ 100.
According to your percentile, on applying this formula you can expect a rank around 15,900. This is only a probable rank. You can expect a rank in a similar range. Also, the ranks are expected to change after considering the Results of the April session as the rank list will be prepared after considering the scores of both the sessions.
Best of luck!
Related Questions
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates BrochureYour Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.