I got 90.99 percentile in jee mains 2019...can i get admission in VNIT Nagpur if I'm from bihar and obc category... For cs branch
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Answer (1)
27th Feb, 2019
Helloo..
The formula to calculate the approximate rank is :
(100-percentile)*874469/100.
If we implement your percentile in the formula your predicted rank will be around 78,790.
You have no or very little chance of getting the seat in VNIT Nagpur. Not to worry you will be having one more chance in April and I request you to improve your percentile so that you can get the seat.
For details about closing ranks in VNIT Nagpur please visit the link;
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-vnit-nagpur/amp
All the best..
The formula to calculate the approximate rank is :
(100-percentile)*874469/100.
If we implement your percentile in the formula your predicted rank will be around 78,790.
You have no or very little chance of getting the seat in VNIT Nagpur. Not to worry you will be having one more chance in April and I request you to improve your percentile so that you can get the seat.
For details about closing ranks in VNIT Nagpur please visit the link;
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-vnit-nagpur/amp
All the best..
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