I got 90.99 percentile in jee mains... Obc... Bihar state.... Cs branch... Chances?... Anyone
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Hii Vaibhav,
your rank will be approximately 78789 according to the formula ,rank= (100- NTA percentile score ) X 874469 /100.
vaibhav last year closing rank was 4454 for Computer Science Engneering in Motilal Nehru University.
so at this rank it is very difficult to get admission in this college.
for other courses you can see cutoff using this link-
https://www.careers360.com/university/motilal-nehru-national-institute-of-technology-allahabad-prayagraj/cut-off
although you can get other college for CSE.
first predict your rank using the link given below-
https://engineering.careers360.com/jee-main-rank-predictor
and then predict the college you can get at your rank-
https://engineering.careers360.com/jee-main-college-predictor
hope you understad
thank you.
As per your percentile I.e.,90.99 and u belong to OBC category u do have the chances of getting new NITs.
Hope this information is relevant to your question.
Thank you:)
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