In 2018, under All India Rank, 88634 secured a seat in B.Tech in CSE in UIET Kurukshetra. Now that was 2018 cut off. Your All India Rank can be calculated by the formula 100-your percentile*869010/100 where in 869010 is the no.of Candidates who appeared for JEE Mains, January session. Going by that formula, your All India Rank is 70737. Cut offs depend on various factors such as total no .of seats available, difficulty of the exam, previous year cut offs, no.of Candidates appearing for the exam and no.of Candidates applying for a course. But with an All India Rank of 70737, your chances are decent for a seat in UIET. For the complete list of colleges that you have a chance at, please use our College Predictor:

Hey!

With 91.8 percentile in jee mains, you are eligible to get admission in Uiet Kurukshetra as per previous years records. Also, there are chances for you to get admission in NITs, but you might not get the desired branch. You are also eligible to get admission in IIIT Pune. To know more, kindly use the tool given below

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