I got 92.96% in jee main 2020 .get any collage admission
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You can calculate your rank using the below formula-
100 - your total percentile score is the percentage of people ahead of you. 869010 are the number of candidates appeared for Jan exam. Rank formula is (100 - your total score) X 869010 /100.
Based on your percentile score your rank will be around 61,000. With this rank your chances of getting a seat are very low untill and unless you have any caste reservation.
Previous years cutoff trends-
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-top-nits/amp
Dear Afsal, you haven't mentioned your State and Category. This is important because the opening and closing ranks for Home State Candidates and Other State Candidates are different. Please do let us know these details and we shall let you know relevant information.
Meanwhile, Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 61178 . Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.
With this percentile though you qualify for JEE Advanced, you may have to appear for April session for any chances in NIT if you belong to General Category. Now to predict colleges, please use our college predictor:
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