Answer (1)
Hrisheekesh Singh 31st Jan, 2020

Hey Sreekripa,

According to the formula (100 - your total score) X 112679 /100 your estimated rank is coming out to be AIR 5070 which is a decent rank for JEE- Main paper 2. Your overall rank can vary as the number of students appearing in the April attempt may increase.

You have not mentioned your category here. So these are cutoffs of 2019 for the General category of some top notch colleges to pursue B. Arch.

MNIT, Jaipur - 940

MANIT, Bhopal - 1807

NIT, Callicut - 821

NIT Hamirpur -3934

NIT Patna - 4686

NIT Raipur - 3190

NIT Rourkela - 1717

NIT Tiruchirappalli - 1189

VNIT Nagpur -897

According to the rank mentioned above, you cannot make up much score which is required for getting admission into top NITs. You are very close to the previous year cutoffs so there are chances that you get NIT Patna or NIT Hamirpur. You can try for the state level colleges or some private institutions in your reach. Or you can work hard for April attempt to score higher and get into a good institution.

Your one-stop B.Tech Counselling package with Full-Length JEE Main Mock Tests, 15+ College Predictors, a printed Almanac with 1000+ FAQs on Admissions & more - B. Tech Companion

You may go through the link mentioned below for the JEE Main paper 2 college predictor to get the list of colleges you are eligible and don't forget to mention your category and Domicile state next time.

Link - JEE Main College Predictor

Hope it helps you.

Good Luck!

2 Comments
Comments (2)
31st Jan, 2020
Thanks🙂🙂
Reply
31st Jan, 2020
Sreekripa Kripa It's my pleasure
Reply
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