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Hello Aspirant.
As you've mentioned that you've 95.8 percentile and you're also from general category then according to the rank formula.
Rank=(100-percentile)*8690.10
Your rank is around 32,250-32,300. At this rank you're not eligible for NIT. If you have any of the required quota then you might be eligible to get into NIT.
Best of luck
B.Tech/B.Arch Admissions OPEN
Hello aspirant,
95.8 percentile is good percentile but to get you desired college , 98 plus percentile will be required by you. There is one chance in April session so practice more and try to get 98 plus percentile to get old NIT colleges.
You can calculate your rank by the formula
(100 scored percentile)×869010 /100
That means your rank is 39105 which means you have little hope to get NIT .
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