I got 95.96 (General) NTA Score in JEE Main Jan 2019 . What could be rank i can get ? which colleges i can get admission?
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Hello aspirant
Considering the total number of students to be 10 lakhs and using the below formula.
Rank= (total number of students -(percentile*0.01*number of students))
Your rank will be about 40400
U may probably get into an nit but with this rank you will not be able to get the top branches like cse.
Thank you
Hello
It is difficult to predict the actual rank or JEE Advanced qualifying marks as for the first time JEE Main is being conducted twice and rank will be based on NTA percentile score but you may calculate your expected rank by this formula-
874469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 874469 / 100.
If the number of candidates for April exam increased to 1400000 then your final rank shall be (100- your total score) * 1400000/100
With 95.96 percentile you also have decent chances to qualify for JEE Advanced exam.
To check the colleges where you can get admission based on your rank, you can use the College Predictor tool using the link below-
https://engineering.careers360.com/jee-main-college-predictor
Good Luck!
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