I got 96.01 percentile in jee main paper 2 b.arch i belong to obc ncl what rank can i get
Answer (1)
1st Feb, 2019
Hello Kiran
Congrats for scoring 96.01 percentile in JEE main paper 2.
There is a pedicted formula from our team to predict rank
Total No of students = 145386
Formula
Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100
So your predicted rank =5815 approx
Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.
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