I got 96.2861368 percentile in jee mains 2021, what is AIR and OBC category rank for the above percentile
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With a CRL of 96.286 in JEE Main, you have fair chances of securing a CRL anywhere between 40-42k, with a corresponding OBC NCL Rank between 9-11k. You do have fair prospects of securing a seat in many of the NITs, IIITs, GFTIs at this Rank.
For more information about JEE Main College Prediction do follow the link below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Hi
It's difficult to predict as percentile vs rank in JEE main depends upon a number of factors like
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number of students that appeared in the jee main exam,
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kind of marks obtained by them ,
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toughness level of the jee main examination for different shift etc.
But yes,
with 96.2861368 percentile
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your rank will be around 37993 - 42709 as per our rank predictor at
Your obc rank will be around 11k
With your rank , you have chances in following nits which are listed below along with their closing rank under other state in 6th round of josaa counselling 2020:-
----------) National Institute of Technology, Manipur:- electrical engineering:-11152 obc rank
-----------) National Institute of Technology, Andhra Pradesh:- Mechanical Engineering (4 Years, Bachelor of Technology):-11272
-----------) National Institute of Technology, Nagpur:-Mining Engineering:-13243
To help you further,
To give you an idea of qualifying cut off, JEE mains 2020 qualifying CUT OFF percentile is given below for different category
>>>> General :- 90.3765335
>>>> GEN-EWS :- 70.2435518
>>>> OBC-NCL :- 72.8887969
>>>> SC :- 50.1760245
>>>> ST :- 39.0696101
>>>> PwD :- 0.0618524
You can check the same at our page the link is provided below
https://engineering.careers360.com/articles/jee-main-cutoff
To get the complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Thankyou
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