I got 96.8559175 percentile in jee mains paper 2 ...and I belong to obc .. please may I know what will be my rank approx?
New: Direct link to apply for JEE Main 2025 registration for session 1
Also Check: Crack JEE Main 2025 - Join Our Free Crash Course Now!
JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQs | Video Lectures
JEE Main 2025: Preparation Guide | High Scoring Topics | Study Plan 100 Days
Hello Imran,
Congrats for scoring 96.85 percentile in JEE main paper 2.
We can't say that which college you wil get but we can predict the rank with this percentile .
There is a pedicted formula from our team to predict rank
Total No of students = 145386
Formula
Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100
So your predicted rank =5815 approx
Its hard to predict your Catagory wise rank.
Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.
Firstly congratulations for the result you have got. You can calculate your rank by using the Rank Formula = (100 - your total score) X 145386 /100.your approx rank is 4579
Hope my answer will help you.
For any further queries drop a comment below
Thank you
Related Questions
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates BrochureYour Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.