I got 97.66 percentile in JEE paper 2 can I get in an NIT I am OBC architecture please help
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Hello
It is difficult to predict the actual rank or JEE Advanced qualifying marks as for the first time JEE Main is being conducted twice and rank will be based on NTA percentile score.
You may calculate your expected rank.
145386 are the number of candidates appeared for the JEE Main paper 2 January exam. So rank formula is (100- your total score) * 145386/ 100.
Your expected rank will be around 3402.
You can check the previous year cutoff for reference and to have an idea about the rank required for admission
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
Good Luck!
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