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I got 97.66 percentile in JEE paper 2 can I get in an NIT I am OBC architecture please help


Shoukath Ali 2nd Feb, 2019
Answer (1)
ruchika.chauhan Expert 2nd Feb, 2019

Hello

It is difficult to predict the actual rank or JEE Advanced qualifying marks as for the first time JEE Main is being conducted twice and rank will be based on NTA percentile score.

You may calculate your expected rank.
145386 are the number of candidates appeared for the JEE Main paper 2 January exam. So rank formula is (100- your total score) * 145386/ 100.


Your expected rank will be around 3402.
You can check the previous year cutoff for reference and to have an idea about the rank required for admission

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

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