I got 97.79 percentile in Jee mains 2020.what will be my crl and obc ncl rank . further can i get admission in nit trichy
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Hello Sir
If you consider previous year cutoffs then your rank will be around 38000. Rank formula: 874469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 874469 / 100
You can get your Home State Nit's but not CSE.
For more info: https://engineering.careers360.com/articles/jee-main-cutoff
You can calculate your expected rank using the formula given below
(100-total percentile)*869010/100
In your case it is
(100-97.79)*869010/100=19205.
So your overall rank will be around 19205.
Your category rank will be around 7k-9k.
Considering 2019 JoSAA seat allotment a candidate belonging to OBC-NCL with rank 7162 got seat in production engineering and a candidate with 6892 rank got seat in metallurgical and materials engineering.However, cut off is subjected to change it may increase or decrease slightly.
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