Hello Aspirant,

It's difficult to tell you the exact about the qualifying cutoff & exact rank. You may calculate your expected rank by this formula

100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Using the formula
(100 - your total score) X 869010 /100

Your probable rank will be 17,119.

Based on this percentile, You can have the chances to get National Institute of Technology Raipur, Indian Institute of Engineering Science and Technology Shibpur, National Institute of Technology Silchar, National Institute of Technology Uttarakhand, National Institute of Technology Patna Etc.
for Mechanical & Computer Science Engineering.

To know your other admission possibilities, You can use JEE Main College Predictor tool given below.

Good Luck!