Hello there,
You have missed out to mention few details like your home state and your category. Nevertheless, I'm providing you the names of the colleges.

According to the formula, [100-98.02*869010/100], your All India Rank is 17206 approximately. Since you haven't mentioned your category, I'm assuming that you are from the general category.

Here is a list of NITs where you can apply with this rank :
1. NIT Sikkim
2. NIT Meghalaya
3. NIT Manipur
4. NIT Mizoram
5. NIT Arunachal Pradesh
6. NIT Agartala
For more information regarding NIT cut-off, you can visit the link given below:
https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

Here is a list of other colleges where you can apply with this rank:
1. Amity University
2. Loyola College
There are many other good colleges too.

You can also use our college predictor:


Also note that the cut-off rank changes every year depending on the difficulty of the paper,and the number of candidates appearing for it.

Hope this answer helps you.
Good luck!!

With 98.02 percentile you cannot get into top NITs Computer Science Engineering. Your rank will be around 17,000. With this rank, you can get into the following NITs for CSE -

1. NIT DURGAPUR
2. NIT HAMIRPUR
3. NIT WARANGAL
4. NIT ALLAHABAD
5. NIT JALANDHAR

And you can try in some private universities of your state as well. Some top ones are -

1. KJ Somaiya College of Engineering, Mumbai
2. Swami Vivekananda College
3. Amity University
4. Loyola college

Best wishes. Thankyou.

JNEC Aurangabad

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