I got 98.4713478 percentile in JEE Paper 2. What will be my rank for General Cat ? And which college can I predict
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Hi Irfan,
Congratualtions on your succesfull results. This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around
2,222
.
Based on this rank, you can get the following colleges:
1. National Institute of Technology, Hamirpur
2. National Institute of Technology, Raipur
3. National Institute of Technology, Patna
4. BIT Mesra, Ranchi etc.
Look at the opening ranks and closing ranks for last year using the link given here(https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning) and predict which colleges you might be eligible for.
To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below: Https://engineering.careers360.com/articles/jee-main-paper-2-result Thanks,
ReplyIf we consider category wise for general quota the rank may be lesser than 2222. Am I correct ?
I also presume that the cut off ranks for last year started by careers360 is category rank.
Please anyone clarify my point.
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