146 Views

I got 98.9145 percentile. Which not I get? Is I am lost it?


hashimmkba 22nd Feb, 2019
Answers (3)
spandana devasani 25th Feb, 2019

Hello Hashim,

JEE Main is conducted twice an year(from 2019) by the National testing Agency(NTA) to provide admission into various undergraduate courses in Institutions like NITs,IIITs,CFTIs etc..One session of JEE main is already over in January and NTA also started receiving applications for those who want to appear for JEE main second session which is conducted in April.

By the percentile you scored, you will definitely be qualified to appear for JEE Advanced which is conducted for admissions into undergraduate courses in various IITs. And also since, percentile is introduced this year , it is unable to predict exactly whether you have a chance in NITs or not. But based on the percentile, you can calculate your All India Rank(AIR) using the below given formula:

As per the statistics given by the NTA, 8,74,679 candidates appeared for the exam across four days with two sessions each i.e for a total of eight sessions.There are a total of 15 students who scored 100 percentile in these sessions.

To calculate you JEE main score, you need  to know the percentage of people ahead of you.For that, you have subtract your percentile from 100 and it is multiplied with 8,74,679 divided by 100.

Therefore, the formula to calculate the JEE Main 2019 for January Session:

JEE Main rank(probable)=(100-NTA percentile)*874679/100

So, your probable rank will be around 9500, which is actually a good rank but as said, it is not an accurate prediction. And you can aim for a better percentile if you want a good branch in a good NIT. So, I would suggest you to give a second attempt to just in case improve your percentile.

Thankyou!



1 Comment
Comments (1)
14th Mar, 2019
How much mark needed for advanced?
Reply
narendersingh3163_8250305 Student Expert 25th Feb, 2019

Hi aspirant,

You have scored a good percentile so don't worry about getting a good NIT. According to your percentile your general rank will be probably under 10,000. Under this rank ,you will able to get  CSE branch in NIT jamshedpur and also you will get good branch in other NITs like ece,mechanical,eee ,etc.

Good luck.

JEE Main Exam's High Scoring Chapters and Topics

This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.

Download EBook
Srikanth Ganna 25th Feb, 2019
Helloo..



The approximate rank predictor formula is (100-percentile)*874469/100.



If we apply your percentile in the formula your rank will be around 9,500.



For this rank you will get the seat in best nits  and you may also get the seat you wish .



Hope you understand...

All the best..









Know More About

Related Questions

UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest CTC 50 LPA , 100% Placements
Amrita University B.Tech 2025
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Jain University B.Tech Admiss...
Apply
100% Placement Record | Highest CTC 42 LPA | NAAC A++ Accredited | Ranked #68 in India by NIRF Ranking 2024
VIT - VITEEE 2025
Apply
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited
10 mock test with explanation...
Apply
Practice free full length mock test with explanation for JEE Main exam
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities In QS Asia Rankings 2025 | Scholarships worth 210 CR
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books