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Hey Kanth
Thanks for your query. In sastra university the eligibility criteria is meant by the marks you scored in 12th and your JEE MAINS percentile.There is a total of 165 marks divided as follows:
12th % * 0.75 + jee mains% * 0.25
Out of 165 your rank and seat is determined.
B.Tech/B.Arch Admissions OPEN
Admissions in SASTRA university is made on the basis of the two streams where in stream 1 consideration will be on the basis of JEE Main marks along with the 10+2 marks while in stream 2 only 10+2 or equivalent marks will be considered. Candidates must check the eligibility criteria before applying for Sastra B.Tech 2019 admission. The rank list will be released separately for the respective streams on the basis of which candidates will be called for the counselling.
You can apply for it and wait for the rank list.
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