JEE Main 2025: Rank Predictor | Admit Card Link | January Session Exam Analysis
JEE Main 2025: Memory Based Question: Jan 23 - Shift 1 | Shift 2 | Jan 22: Shift 1 | Shift 2
JEE Main 2025: High Scoring Topics | Sample Papers | Mock Tests | PYQs
Hello aspirant
Considering the total number of students to be 10 lakhs and using the below formula.
Rank= (total number of students -(percentile*0.01*number of students))
This means you have a rank of 498960 . If you are general u don't get any nit nor do u qualify for jee advance
Better luck next time
This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile