I have 84.21 pr in jee main paper 2 my cast is obc I have addmission in nit

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I have 84.21 pr in jee main paper 2 my cast is obc I have addmission in nit

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Kugasiya Vivek rameshbhai 25th Jan, 2020

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Rahul Student Expert 25th Jan, 2020

Hello aspirant,

100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.

Rank formula is (100 - your total score) X 112679 /100.

So, based on your percentile score your rank will be around 17000. According, to the previous years cutoff trends your chances are quite low unless you have reservation.

Previoys years cutoff trends

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

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Nikhitha Sai 25th Jan, 2020

Hello aspirant. Congratulations on your score. First check the rank.
Rank can be calculated this way
(100- your total score)*112679/100
Where 100 is your total percentile score is the percentage of people ahead of you
112679 are the number of candidates appeared for january exam.
Here I will also share the rank predictor link
https://engineering.careers360.com/jee-main-rank-predictor
I would post the college predictor link too, kindly have a look so that you would get the idea
https://engineering.careers360.com/jee-main-college-predictor

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