I have 94.363 percentile in B.arch (jee main paper 2) and I have OBC category too. Is there any chance I can get NIT or any govt college?
The exact prediction would be difficult as JEE Main is being conducted twice by NTA for the first time. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 8,199. With this rank the chances seems less to get a seat in NITs but other colleges you can try. You can also prefer the previous year cutoff to take an Idea about the admission possibilities.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.
Good Luck!
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