i have got 81.2 percentile in jee paper 2...could you please tell what rank can i approximately get
Also Check: Crack JEE Main 2025 - Join Our Free Crash Course Now!
JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQs | Video Lectures
JEE Main 2025: Preparation Guide | High Scoring Topics | Study Plan 100 Days
Hello Arjun
It is difficult to predict the actual rank or JEE Advanced qualifying marks as for the first time JEE Main is being conducted twice and rank will be based on NTA percentile score.
You may calculate your expected rank.
145386 are the number of candidates appeared for the JEE Main paper 2 January exam. So rank formula is (100- your total score) * 145386/ 100.
Your expected rank will be around 27332. This is the probable rank and may change according to the number of candidates which will appear for the JEE Main April exam.
Good Luck!
Related Questions
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates Brochure
Your Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.
