I have got 91.52 %in JEE mains which colleges should I get In Maharashtra through jee quouta ..pls help...

Hello student,

Congratulations for scoring such good percentile in JEE mains 2021. With this good percentile, you can get admission in some of the decent good colleges of the state. In some  of the below colleges, you may have to compromise with your branch preferences.

Here is a list of some of those colleges:

• JSPM Rajarshi Shahu College of Engineering
• Shah and Anchor College of Engineering
• AISSMS
• PVPPCOE
• KK Wagh College of Engineering
• Datta Meghe College of Engineering
• DY Patil College of Engineering
• Sinhagad College of Engineering

Click here to check out the previous year cut offs

Click here to get the prediction of colleges available to you

I hope this helps, All the Best!

Hello,

Considering the previous year cut off in MHT CET Round 2 counselling based on JEE Main score here is the list of institutes in which you have chances of getting seat with the given percentile

• Dr. D. Y. Patil Pratishthan's D.Y.Patil College of Engineering Akurdi, Pune: Information Technology
• K. K. Wagh Institute of Engineering Education and Research, Nashik: Computer Engineering
• Mahatma Gandhi Missions College of Engineering, Hingoli Rd, Nanded: Civil Engineering
• Sinhgad College of Engineering, Vadgaon (BK), Pune: Computer Engineering
• MKSSS's Cummins College of Engineering for Women, Karvenagar,Pune: Electronics and Telecommunication Engg
• Dr. D.Y.Patil Institute of Engineering, Management & Reseach, Akurdi: Computer Engineering

The cut off changes every year depending on the total number of candidates appeared, difficulty level of examination and total number of seats available etc.

To check the previous year cut off click on the link given below

https://engineering.careers360.com/articles/mht-cet-cutoff

To know the colleges in which you have chances of getting seat you can use JEE Main college predictor tool using the link below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer