JEE Main 2025: Rank Predictor | Admit Card Link | January Session Exam Analysis
JEE Main 2025: Memory Based Questions with Solution Jan 22: Shift 1 | Shift 2
JEE Main 2025: High Scoring Topics | Sample Papers | Mock Tests | PYQs
Hello aspirant
Considering the total number of students to be 10 lakhs and using the below formula.
Rank= (total number of students -(percentile*0.01*number of students))
I believe you want to say 92.7 percentile
Your rank comes out to be 73000 so indeed you are qualified for jee advance
All the best
This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Eligibility | Application | Exam Pattern | Admit Card | Preparation Tips | Answer Key | Result | Accepting Colleges
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile