I have got 93.75 percentail in jee main and I am general category and belongs to tamilnadu. can I get iiit
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To caculate your rank with the help of your percentile, we should use the formula:
(100-your total percentile)*869010/100. Going by this formula, your rank will be 54313. Now this is for January session. If the no.of Candidates appearing for JEE Mains April session is increased to 12,00,000 then your final rank is calculated using the formula: (100 - your total score) X 12,00,000/100.
With this rank, chances in good branches might in NITs and IIITs might be less. But should you plan on appearing for JEE Advanced, you will qualify as the expected qualifying percentile is 85 and above.
If you look at the previous cut offs IIIT Kanchipuram as mentioned here:
|
CSE: |
15862 |
|
ECE: |
20778 |
|
ME: |
29180 |
|
Smart Manufacturing: |
38737 |
|
B. Tech-M.Tech |
|
|
Mechanical Engineering in Product Design |
38623 |
|
Advanced Manufacturing |
40529 |
|
Computer Science and Engineering (Integrated Dual Degree) |
23855 |
|
B. Tech. -M.Tech Electronics Communication Engineering |
|
|
with specialization in Communication Systems Design |
32339 |
|
B. Tech-M.Tech Electronics and Communication Engineering |
|
|
with specialization in VLSI Design |
29735 |
Though cut offs change ever year, with your rank, it might be difficult for IIIT. Now to predict colleges, please use our college predictor:
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