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I have got a percentile of 96.734 in JEE mains Paper I held in Jan 2019. What will be my Expected Rank?


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Deepesh Gupta 19th Jan, 2019
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Dibya Jyoti Mohapatra 19th Jan, 2019

Hello aspirant

Considering the total number of students to be 10 lakhs and using the below formula.

Rank= (total number of students -(percentile*0.01*number of students))

Your excepted generalgener is about 32660. Congratulations u have qualified for jee advance.

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20th Jan, 2019
Dear jyotiSuppose there is a student who have got 94 percentile but there is no student with 95 and something then explain me  the difference between their rank and there is no student between their ranks according to this formula ..I hope you can understand my doubt
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