I have score 66.752120percentile in Jee mains. Will any of engineering instiutes accept with me this percentile ?

Hello Candidate,

your rank will be 3,15,855 based on our rank predictor formula.

Rank predictor formula = ((100 - your percentile)/100)*total number of candidate

Your rank range between 312000 - 316000 .

Based on this rank you able to get private colleges in your area.You not able to get any GFTIs and CFTIs based on this rank.



For getting good college you should write Jee main again in month of April with more efforts.



If any queries remain than comment below.

Good luck...

Hello Aspirant



Use this formula to predict your rank:



Rank=(total number of students -(percentile*0.01*number of students)).here the number of students is 874469. By rank only the cutoff of college is decided .



Here then go for predicting the College by college predictor i will provide link from careers 360.



https://engineering.careers360.com/jee-main-college-predictor



I will suggest you to give the attempt for April jEE mains exam 2019. To get good score and opportunities of Colleges. The above rank which you got by using the formula may differ from official cutoff because the official cutoff was officially released by national testing agency NTA on the month of April you should have to wait till the official cutoff is released.



If you have any questions further let me know.



Thank you!!!!