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I have scored 92.6 percentile in my JEE main 2019 .What will be my rank.Am I eligible for NIT Rourkela?


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Padmaja Dash 11th Dec, 2018
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Answer (1)
suresh venkat 20th Jan, 2019
Hello padmaja,

We have a formula for that

(100-your percentile)*(874469/100)

Here 874469 are the number of students applied for jee mains.

So,from above formula,your percentile is 92.6.

So,

Your rank would be around 64710.

This is an approximation, so dont completely depend on it please wait till the official results are out.

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20th Jan, 2019
Thank you Suresh
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