1002 Views

I have scored 92.6 percentile in my JEE main 2019 .What will be my rank.Am I eligible for NIT Rourkela?


Padmaja Dash 11th Dec, 2018
Answer (1)
suresh venkat 20th Jan, 2019
Hello padmaja,

We have a formula for that

(100-your percentile)*(874469/100)

Here 874469 are the number of students applied for jee mains.

So,from above formula,your percentile is 92.6.

So,

Your rank would be around 64710.

This is an approximation, so dont completely depend on it please wait till the official results are out.

ALL THE BEST







B.Tech/B.Arch Admissions OPEN

Apply to Amity University, Noida B.Tech Admissions 2024

1 Comment
Comments (1)
20th Jan, 2019
Thank you Suresh
Reply
JEE Main College Predictor

Predict your top engineering college admission chances based on your JEE Main All India Rank & NTA Score.

Use Now

Know More About

Related Questions

Admissions & Career Expo 'L.A...
Apply
50+ Institutes | 200+ Programs | ₹2000 cashback on Application fee | 100+ Scholarship | On-spot admission offer
Amity University, Noida B.Tec...
Apply
Asia's Only University with the Highest US & UK Accreditation
Lovely Professional Universit...
Apply
India's Largest University | 100% Placements Record | Highest CTC 3 Cr PA | Application End Date : 15th Jun'24
Starex University | B.Tech A...
Apply
Ranked #12 in University category by NIRF 2024 | Collaboration with IBM- ICE for Hi-Tech Programs
Manav Rachna University B.Tec...
Apply
MRIIRS accredited A++ grade by NAAC | 39000+ Alumni network
Bennett University B.Tech Adm...
Apply
Scholarship Seats Application Deadline - 25th June 2024 | Highest CTC 1.37 Crore Per Annum
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books