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I have scored 95.33 percentile in jee paper 2. what will be my rank?..


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Answers (4)
Arunima Singh 1st Feb, 2019

Hi Keerthiraman,

Congratulations on your amazing result!

According to your percentile, your probable General category rank is 6810 or 6811. This rank is subject to the total number of students who had apperared for the January session of the JEE Paper 2 and you can expect it to vary after the NTA releases the final result post the April session. You can use the following formula for future reference -

Rank Predictor - (100-your percentile)x1,45,386/100

Where 1,45,386 is the total number of candidates that appeared for the January exam. This number will change when you calculate your final rank in April.

Congratulations once again, great job done. I hope I could help you and I wish you all the very best.

1 Comment
Comments (1)
Sir... Would i enter enter nits.?
Reply
kashishjuneja2000_8032841 Student Expert 1st Feb, 2019

Hey,

your rank is 6789. But this is just an estimate about your rank. You final rank will declared by NTA after the april session. The april session might fluctuate the ranks as the total number of students appearing for the exam change. So wait for the final result.

All the best

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Heena Gagwani 1st Feb, 2019

The approximate rank for percentile 95.33 in JEE Mains Paper 2 will be around 7000(+-). Note that this is just an estimation and it can change JEE Mains is again conducted in April.

If you still have any queries feel free to ask in the comment section down below.

yash sarraf 1st Feb, 2019

HEllo sir

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this is not the final rank.It will change based on the april session of mains.Hope this helps.

Good Luck!

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