JEE Main 2025: College Predictor | Marks vs Percentile vs Rank
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HELLO MADHAV!
First of all congrats for scoring such awesome percentile.I can give you rough idea about your rank under general quota using this formula:Probable ranl=(100-percentile score)*145386/100,where 145386 is total number of candidates that appeared in 1st phase of jee mains of paper2.Your rank will be around 2.6k under general category.To get NITs you need rank under 2k.For BIT mersa closing rank is 3.8k under HS quota and 1.8k under OS quota.For surety wait till arpil.NTA will release rank after compilation of both phases result.You still have one attempt for jee mains paper2.
Let me know if you have any other queries.
GOOD LUCK!
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