I received 97.54 percentile in Jee main.I can get admission in NIT KURUKSHETRA
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Still your chances are pretty good.
Good luck for your future
A formula is given to calculate rank by National Testing agency .The formula is No of Candidates apperared in exam/100 *(100- Nta score )So the total no of Candidates appeared was 869010.Ao your rank will be 21377.
The cutoff mentinoned below are for general Categories..
Cutoff for last year of Nit krukshetra was
Electronics and communication-Other state
Closing rank -11467
Computer science
Closing rank-6313
If you want to predict college based on your Percentile and rank then you can visit the link mentioned below
Thanks
All the very best
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