I scored 96.01 in jeemain paper 2 i belong to obc what will be my category rank
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Hello Kiran,
With the NTA percentile you mentioned your probable General rank is around 5801. This rank is calculated while considering that total number of students appeared for this exam is 1,45,386, also it may change after second phase of jee mains which will be conducted in the month of april. For knowing your category rank you can comment your possible marks out of 360 and I can help in knowing your probable category rank.
Good Luck !!!
Hello aspirant, well done. 96.01 is a good score
Based on your score and previous year trends your rank will be nearer to (100−96. 01)×1,45368/100=5800.And you will be defenitely eligible to write jee advanced exam. And you have chances with National institute of Engineering.
Good luck
We cannot guess the category rank.Bjt we have a formula to calculate the general rank. The formula is (100-percentile)*145386/100.
Here 145386 is the total no of candidates appeared for the exam.
So if you implement your percentile with the above formula your predicted rank will be around 5,800.
All the best...
Thank you for consulting careers360..
Firstly congratulations for the result you have got. You can calculate your rank using Rank Formula = (100 - your total score) X 145386 /100.your rank will be around 5800 .
Hope my answer will help you
For any further queries feel free to drop a comment below
Thank you
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