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I scored 96.01 in jeemain paper 2 i belong to obc what will be my category rank


Kiran 1st Feb, 2019
Answers (4)
Aaditya 1st Feb, 2019

Hello Kiran,

With the NTA percentile you mentioned your probable General rank is around 5801. This rank is calculated while considering that total number of students appeared for this exam is 1,45,386, also it may change after second phase of jee mains which will be conducted in the month of april. For knowing your category rank you can comment your possible marks out of 360 and I can help in knowing your probable category rank.

Good Luck !!!

Abhinav p v 1st Feb, 2019

Hello aspirant, well done. 96.01 is a good score

Based on your score and previous year trends your rank will be nearer to (100−96. 01)×1,45368/100=5800.And you will be defenitely eligible to write jee advanced exam. And you have chances with National institute of Engineering.

Good luck

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Srikanth Ganna 1st Feb, 2019
Hello..

We cannot guess the category rank.Bjt we have a formula to calculate the general rank. The formula is (100-percentile)*145386/100.

Here 145386 is the total no of candidates appeared for the exam.

So if you implement your percentile with the above formula your predicted rank will be around 5,800.

All the best...

Thank you for consulting careers360..




Jayasurya Reddy 1st Feb, 2019
Dear aspirant.,

Firstly congratulations for the result you have got. You can calculate your rank using Rank Formula = (100 - your total score) X 145386 /100.your rank will be around 5800 .

Hope my answer will help you

For any further queries feel free to drop a comment below

Thank you



3 Comments
Comments (3)
1st Feb, 2019
Can i get any nit
Reply
1st Feb, 2019
We can't predict as official cutoffs are not yet been declared. But as your rank is good and you fall under obc category ,you may definitely get an NIT.
Reply
1st Feb, 2019
Thanku for ur reply
Reply

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