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i scored 96.2 percentile in jee main 9th january 1st phase .... i am a obc candidate .... am i applicabe for nits now


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roman empire 20th Jan, 2019
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Sai 20th Jan, 2019

Hello Roman Empire..

According to careers360 rank formula,

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 33,230.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So according to expected rank of yours, so you are eligible for jee advanced and you can even apply for nits too.

Hope this helps you. All the best

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20th Jan, 2019
which of the few nits can u please tell
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