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i scored 98.65 in JEE mains B Arch 2020. what is my rank and what are my chances of getting a seat in NIT, Calicut?


jaison 14th Dec, 2019
Answers (3)
Inayath 23rd Jan, 2020
Hello aspirant,

Congratulations for your score you got. 98.65 percentile is really a good result. So there is possibility of getting a seat, but still it depends on which category you belong.
But I'm sure you'll get a seat. According to your percentile your rank will be approximately 1521.1665, but categories and quotas play a major role.
College predictor may help you the most. Here is the link: College predictor (https://edu.app.link/T53GAoi4t3)
Hope you get admitted to one of the best colleges.

All the best.

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2025

Harshita Gupta 23rd Jan, 2020
Hey,

You rank will be around 1521.

You can also Calculate the rank using the formula:
(100 - your total score) X 112679 /100 .

100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.

If the number of candidates appearing for April session increase or decrease than your rank will change accordingly.
Considering previous year cut-offs, you might get admission in NIT Calicut.
For architecture, the cut-off for general category home state Candidate was 1668 rank in 2019.

You haven't mentioned your category, and so predicting the exact details is difficult, but kindly check the link below to see previous year cut-offs:
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut/amp

Kindly use the College predictor mentioned in the link below to see your admission possibilities:



Hope this helps!
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Misbah Anjum N 23rd Jan, 2020

Hello!

Congratulations! With such a high percentile, I believe that you can get into NIT, Calicut!

To predict if you can get into your desired college, first calculate your rank!

To calculate the rank for B.Arch:

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) X 112679 /100.

To check about the colleges:

Refer to the previous year cutoff after calculating the rank from the formula mentioned above.

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b- planning/amp

Use our college predictor tool too:

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