I want prediction for Paper 2 score. My percentile is 98.89 in JEE Main of Jan 2020

Hi  Binayak,

You got 98.89 percentile in JEE main exam, your rank would be approximately in between 1000 to 2000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your expected rank using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112680, your rank will be around 1250. However as the no. of students in April changes, your rank will change according to that

On the basis of your percentile, the colleges you will get are:

• Malaviya National Institute of Technology Jaipur
• Maulana Azad National Institute of Technology Bhopal
• National Institute of Technology Calicut
• National Institute of Technology Hamirpur
• National Institute of Technology Patna
• National Institute of Technology Raipur
• National Institute of Technology, Rourkela
• National Institute of Technology, Tiruchirappalli
• School of Planning & Architecture, Bhopal

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is :

JEE Main Architecture/Paper-2 College Predictor 2020 - Predict your College

JEE Main Architecture/Paper-2 College Predictor - Know your college admission chances based on your Home State, Caste, Gender, Exam Result a ...