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I want to study B. Tech Biotechnology in IIT, Kharagpur. What should be my ranking in JEE(Adv) for such study? l am a General candidate.


Joydev Chakraborty 28th Mar, 2020
Answer (1)
Maria Sunny 7th May, 2020

Hello,

According to JEE Advanced 2019 the cut off rank for Biotechnology was 6312 for general category candidates.The cut off score depends on a variety of factors and may change every year.Check out the link below for more details :

https://engineering.careers360.com/articles/jee-advanced-cutoff-for-iit-kharagpur

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