Iam from Andra Pradesh OBC girl.I got 95.55percentile in jee mains2020january.can I get admission in AP nit any branch?
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Hello,
Your expected rank will be around 39105.Your expected rank can be calculated by the formula (100-your total percentile)*869010/100
869010 is the total number of candidates appeared in January session.The expected number of candidates appearing in April session will be 1200000
then your expected rank can be calculated by the formula (100-your total percentile)*1200000/100
And you category rank will be in between 10000-12000 based on 2019 cut off trends you may get admission in NIT, AP in
- Biotechnology
- Chemical Engg
- Mettalurgical and Materials Engineering
You can predict the colleges in which you may get seat by clicking the link below
Hi Divya,
As per this formula
(100-your percentile)*869010/100
Your rank comes out to be approx 39,105. If it is to be assumed that the number candidates by april session would go up to 12,00,000. Replacing 869010 with 12,00,000. (100-your percentile)*1200000/100
Your rank comes out to be 54,000. Last years maximum opening rank for OBC was 12030. So the chances are tough for you to make it.
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