Iam jeemain score 60.42 obc +2 exam atten 2019 my mark get chemical engineering in NIT rourkela,
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Hello sir
Well, it's very difficult as of now,to predict the cutoff for colleges of JEE mains and for jee advance based on percentile.You can first calculate your rank by rank=(100-percentile)*874469/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting and also the advance cut off.But remember this is not the final rank.It will change based on the april session of mains.To further predict colleges visit https://engineering.careers360.com/jee-main-college-predictor .But personally I don't thijnk that you can qualify mains wiht this percentile.Hope this helps.
Good Luck
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