Question : If 5416*6 is a perfect square then the digit at * is:
Option 1: 9
Option 2: 4
Option 3: 6
Option 4: 5
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Correct Answer: 9
Solution : A perfect square ending with '6' can only have an odd digit at its ten's place, i.e., the second last digit. Thus second and last options are eliminated. Now, $\sqrt{541656}< 736$ $\sqrt{541696}=736$ Hence, the correct answer is 9.
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Question : If 5416*6 is the perfect square, then the digit at the '*' place is:
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