if A =1*2, B=2*2,c=3*2. then KNOT is written as 120, how is DIYA written in the same code language
Answer (1)
25th Dec, 2021
Hello Aspirant,
See this is very simple aptitude problem, in which every alphabet is given with code of two times of their position like A is 1st alphabet so A=1*2 and likewise B=2*2 and so on, so KNOT can be written as
K = 11*2 = 22
N = 14*2 =28
O = 15*2 = 30
T = 19*2 = 38
Now sum all above values i.e. 22+28+30+38 = 120. SImilarly for DIYA, it will be written as :
D = 4*2 = 8
I = 9*2 = 18
Y = 25*2 = 50
A = 1*2 = 2
So DIYA will be 8+18+50+2 = 78. So code for DIYA is 78.
I hope this information helps you.
Good Luck!!
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