Question : If a + b + c = 0, then the value of (a + b – c)2 + ( b + c – a)2 + ( c + a – b)2 is:
Option 1: 0
Option 2: 8abc
Option 3: 4(a2 + b2 + c2)
Option 4: 4(ab + bc + ca)
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 4(a 2 + b 2 + c 2 )
Solution : a + b + c=0 ⇒ a + b = –c --------------(i) ⇒ b + c = –a --------------(ii) ⇒ c + a = –b --------------(iii) Substituting (i), (ii) and (iii) in (a + b – c) 2 + (b + c – a) 2 + (c + a – b) 2 , we get (a + b – c) 2 + (b + c – a) 2 + (c + a – b) 2 = (–c –c) 2 + (–a –a) 2 + ( –b –b) 2 = 4c 2 + 4a 2 + 4b 2 = 4(a 2 + b 2 + c 2 ) Hence, the correct answer is 4(a 2 + b 2 + c 2 ).
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If a + b + c = 1, ab + bc + ca = –1, and abc = –1, then what is the value of a3 + b3 + c3?
Question : If $a + b + c = 0$ and $ab + bc + ca = -11$, then what is the value of $a^2+b^2+c^2$?
Question : If (a + b + c) = 7 and ab + bc + ca = 12, find the value of a2 + b2 + c2.
Question : If a + b + c = 15 and a2 + b2 + c2 = 83 then the value of a3 + b3 + c3 – 3abc:
Question : For real $a, b, c$ if $a^2+b^2+c^2=ab+bc+ca$, then value of $\frac{a+c}{b}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile