Question : If a + b + c = 0, then the value of (a + b – c)2 + ( b + c – a)2 + ( c + a – b)2 is:
Option 1: 0
Option 2: 8abc
Option 3: 4(a2 + b2 + c2)
Option 4: 4(ab + bc + ca)
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Correct Answer: 4(a 2 + b 2 + c 2 )
Solution : a + b + c=0 ⇒ a + b = –c --------------(i) ⇒ b + c = –a --------------(ii) ⇒ c + a = –b --------------(iii) Substituting (i), (ii) and (iii) in (a + b – c) 2 + (b + c – a) 2 + (c + a – b) 2 , we get (a + b – c) 2 + (b + c – a) 2 + (c + a – b) 2 = (–c –c) 2 + (–a –a) 2 + ( –b –b) 2 = 4c 2 + 4a 2 + 4b 2 = 4(a 2 + b 2 + c 2 ) Hence, the correct answer is 4(a 2 + b 2 + c 2 ).
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