Question : If a + b + c = 15 and a2 + b2 + c2 = 83 then the value of a3 + b3 + c3 – 3abc:
Option 1: 200
Option 2: 180
Option 3: 190
Option 4: 210
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Correct Answer: 180
Solution : Given: a 2 +b 2 +c 2 = 83, a+b+c = 15 We know that, (a + b + c) 2 = a 2 + b 2 + c 2 + 2(ab + bc + ca) ⇒ (15) 2 = 83 + 2(ab + bc + ca) ⇒ 225 – 83 = 2(ab + bc + ca) ⇒$\frac{142}{2}$ = ab + bc + ca $\therefore$ ab + bc + ca = 71 Now, a 3 + b 3 + c 3 –3abc = (a + b + c)(a 2 + b 2 + c 2 – ab – bc – ca) Putting the values, we get: = (15)(83 – 71) = 15 × 12 = 180 Hence, the correct answer is 180.
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