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Question : If a + b + c = 15 and a+ b+ c= 83 then the value of a+ b+ c– 3abc:

Option 1: 200

Option 2: 180

Option 3: 190

Option 4: 210


Team Careers360 21st Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: 180


Solution : Given: a 2 +b 2 +c 2 = 83, a+b+c = 15
We know that,
(a + b + c) 2 = a 2 + b 2 + c 2 + 2(ab + bc + ca)
⇒ (15) 2 = 83 + 2(ab + bc + ca)
⇒ 225 – 83 = 2(ab + bc + ca)
⇒$\frac{142}{2}$ = ab + bc + ca
$\therefore$ ab + bc + ca = 71
Now, a 3 + b 3 + c 3 –3abc = (a + b + c)(a 2 + b 2 + c 2 – ab – bc – ca)
Putting the values, we get:
= (15)(83 – 71)
= 15 × 12
= 180
Hence, the correct answer is 180.

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