Question : If (a + b + c) = 7 and ab + bc + ca = 12, find the value of a2 + b2 + c2.
Option 1: 29
Option 2: 31
Option 3: 27
Option 4: 25
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 25
Solution : Given: ab + bc + ca = 12 (a + b + c) = 7 Squaring both sides, we get, ⇒ (a + b + c) 2 = 7 2 = 49 ⇒ a 2 + b 2 + c 2 + 2(ab + bc + ca) = 49 ⇒ a 2 + b 2 + c 2 = 49 – 2(ab + bc + ca) ⇒ a 2 + b 2 + c 2 = 49 – (2 × 12) = 49 – 24 = 25 Hence, the correct answer is 25.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If a + b + c = 1, ab + bc + ca = –1, and abc = –1, then what is the value of a3 + b3 + c3?
Question : If a + b + c = 0, then the value of (a + b – c)2 + ( b + c – a)2 + ( c + a – b)2 is:
Question : If $a+b+c=5$ and $a^2+b^2+c^2=15$, then find the value of $a^3+b^3+c^3-3 a b c-27$.
Question : If p + q = 7 and p2 + q2 = 25, then find the value of pq.
Question : For real $a, b, c$ if $a^2+b^2+c^2=ab+bc+ca$, then value of $\frac{a+c}{b}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile