Question : If A is 40% less than B and C is 40% of the sum of A and B, then by what percentage is B greater than C?
Option 1: 60
Option 2: $56 \frac{1}{4}$
Option 3: $40 \frac{1}{8}$
Option 4: 36
Latest: SSC CGL Tier 1 Result 2024 Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: $56 \frac{1}{4}$
Solution : Let B = 100 So, A = 60 $\therefore$ C = 40% of (60 + 100) = 64 So, B is greater than C by $= (100 - 64) × \frac{100}{64}$ $= (\frac{225}{4})\%$ $=56\frac{1}{4}\%$ Hence, the correct answer is $56\frac{1}{4}\%$.
Candidates can download this ebook to know all about SSC CGL.
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Question : If the salary of Manoj is 40% less than that of Subhash, then by what percentage is the salary of Subhash more than that of Manoj?
Question : If $a: b: c=\frac{1}{4}: \frac{1}{3}: \frac{1}{2}$, then $\frac{a}{b}: \frac{b}{c}: \frac{c}{a}=$?
Question : The sum of three fractions A, B and C, A > B > C, is $\frac{121}{60}$. When C is divided by B, the resulting fraction is $\frac{9}{10}$, which exceeds A by $\frac{3}{20}$. What is the difference between B and C?
Question : If $\frac{a^2}{b+c}=\frac{b^2}{c+a}=\frac{c^2}{a+b}=1$, then $\frac{1}{1+a}+\frac{1}{1+b}+\frac{1}{1+c}$ is:
Question : The numerator of a fraction is a multiple of two numbers. One of the numbers is greater than the other by 2. The greater number is smaller than the denominator by 4. If the denominator $7 + c (c > –7)$ is a constant, then the minimum value of the fraction is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile