Question : If A is 48% more than B and C is 60% less than the sum of A and B, then A is what percentage more than C? (Correct to one decimal place.)
Option 1: 50.8
Option 2: 49.2
Option 3: 50.2
Option 4: 49.8
Correct Answer: 49.2
Solution : Given: A is 48% more than B and C is 60% less than the sum of A and B. Let the value of B be 100. Then, the value of A = $100\times \frac{148}{100}$ = 148 According to the question, C = 40% of (A + B) ⇒ C = 40% of (148 + 100) ⇒ C = $\frac{40}{100} \times 248$ = 99.2 A is more than C by 148 – 99.2 = 48.8 So, the required percentage = $\frac{48.8}{99.2}\times 100$ = 49.2% Hence, the correct answer is 49.2.
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