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If A is a square matrix of order 3 and Aij is the cofactor of the element aij, then value of a_{21} A_{11} + a_{22 }A_{12} + a_{23} A_{13} is ____________


titanarrive2004 12th Nov, 2021
Answer (1)
Subhalaxmi Biswal 14th Jan, 2022

Hello Aspirant,

Here in this, the question is given that A is a square matrix. Aij is the co-factor of aij.

To find - a 21 A 11+ a 22 A 11+a 23 A 13

Solution-

|a 11      a 12    a 13|

|a 21      a 22    a 23|                       = A

|a 31      a 32    a 33|

We are given that Aij is a cofactor of aij.

Hence cofactor of the second column is A21, A22, and A23 respectively.

We know that if we multiply the elements of one row with cofactors of the other row, then their sum will be 0.

So, the sum of a_{21} A_{11} + a_{22 }A_{12} + a_{23} A_{13} = 0.

I hope it helps.

Thank you.

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