if a sample of water contains 50mg of mgcl2 per litre calculate the hardness in terms of caco3 equivalent
Answer (1)
15th Jan, 2021
Hello Candidate,
The Total mass of MgCl2 is equal to 95 amu.
So, as the salt contains the degree of +2 charge, hence the equivalent weight of MgCl2 is equal to 50 amu.
The equivalent weight of CaCo3 is equal to 50 amu.
So, 50 mg of MgCl2= 50 mg of CaCo3. The total amount of CaCo3 equals 50× 10^-3 g/L.
Hence, the hardness of CaCo3 in ppm= 5×10^-2/1000 × 10^6= 5 ppm.
Hope that this answer helps you!!
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