If a student got 98.5 percentile in jee. What will be the rank??
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Well Percentile is the number of students out of 100 how many got marks less than the student. 98.5 percentile means that that student have outperformed 98.5% students in JEE.
Now, considering you are asking for the JEE Mains 2019, there were around 9.65 lakh students who appeared in the JEE Mains 2019 exam. So, the student will have outperformed (98.5* 965000)/100= 950525 students . Which in turn means that the rank of the student should be close to 965000-950525= 14475. Now considering that the total students appeared is far more greater than the cent value, we have a high possibility of lack of precision. So the rank of the student should be around 14000.
Hope this helps :)
Hello Jagadeesh, as per your percentile your rank will be 18000.
I hope It will help.
Thanks.
Hello Jagadeesh,
With a percentile of 98.5 in JEE mains one can get the rank around 16813. This can get him into many good colleges with good branches. Find out your chances for NITs IIITs and GFITs in detailed and comprehensive manner by visiting the following link:
https://engineering.careers360.com/jee-main-college-predictor
All the best
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